EDIT: These are the Answers for this years zio. In case of any discrepancy Write your answer and tag me.
> Q1)a)7300000000, b)5322222, c)9666666666
> Q2)a)90, b)146, c)585
> Q3)a)123, b)72, c)107
> Q4)a)10, b)9, c) 12
Wasn’t it easy this year ?
hi!
yeah it was kinda easy,
for question 1 we have the same answers, except for c)6666666644 yours is bigger
q2) couldn’t solve
3) same answers, someone told me that 127 is also possible for a) i will update when i get the method
did you even consider going to to and then going back?
hi!
my answer for 4th question is
a) 9, b)8, c)11
i have doubt in answers for this question.
@bs1sv13_3137 , Here you go…
Number Frequency Cost Total Cost
your c) 6 8 7 56
4 2 8 16
*56 + 16 == 72
My c) 6 9 7 63
9 1 9 9
*63 + 9 == 72
Ques 4 ) My routes. Line 1 = sequence, Line 2 = bool of movement movement, line 3 = airport number
C A C B C B B B B A A A C B A
1 0 1 0 1 1 1 0 0 1 1 1 1 1 0 == 10
0 0 0 0 0 4 2 2 2 4 1 2 4 2 2
A A A C A A B C C C B A B A C
0 0 0 1 0 0 0 1 1 1 1 1 1 1 1 == 9
0 0 0 0 0 0 0 0 0 0 4 1 4 1 2
A A B A B C C B C A C A A C A
0 0 1 1 1 1 1 1 0 1 1 1 1 1 0 == 11
0 0 4 1 0 0 0 4 0 1 2 4 1 2 0For the fourth one i got 10, 9 12
pretty sure.
for 12:
baccbcacaaca
412331341312
Everyone put 11.I really don’t know why…
Everybody got it wrong. Including me. Congrats. Yours is right.
Wouldn’t the 3c be 119?
Select 3,5,6,8,9,10,13
Also how did you manage to do the second!!
I made a logic (which can be wrong). First we know that the order for 1 is
E1 __ __ __ __ __ __ __ __ __ E6 L6 (E Enter , L leave and no represents train no)
and we can see the arrangements as shown 
We can reach E2 from E1 in 2 ways and so on
If wrong please explain
Well I really need a reliable answer for Q2
7300000000
Hmm… I missed that 3! AAGH!
Interesting… 127 seems impossible but lets wait
@sidmohla
No, 3c will not be 119. Here’s your combination.
3 5 6 8 10 13
4 7 10 6 4 9
B G B B B R
*3 *3 *3 *3
12+21+30+6+4+27 = 100
Make a table for my values and you shall get 107.
My values = 3 5 6 8 9 10 13
I am pretty sure you can’t get 127 or 119.
Q2) part A logic. N = 6, K = 8. K = 8 means next four trains can enter in any order they like after which the last train must leave the yard. In any order because it doesn’t matter when they enter and leave each action costs 1 K and 4 trains entering and leaving will cost us 8 K. Now here are all the cases.Will will consider 6 fixed in all possible positions.
1*6*2345 ]- 2345 can be in any order so 4! = 24
12*6*345 ]- 345 and 12 can be in any order so 3!*2! = 12
123*6*45 ]- 45 and 123 can be in any order so 3!*2! = 12
1234*6*5 ]- 1234 can be in any order so 4! = 24
12345*6* ] - 12345 can be in any order so 5! = 120
24 + 12 + 12 + 24 + 120 = 192.
I tried to do part B with this method but it was very time consuming so I left it. I didn’t try C because I had given up.
EDIT: EXPLANATION.
What I have done is fixed the number 6 in the output place to a particular digit, then I am moving around whatever numbers I can to take a look at permutations. For instance in first line I say 2345 can be in any order. 2345, 5324, and so on can be created without hassle. I have taken its factorial. For those who don’t know what a factorial is google it and read about permutations.
@superty Because we are having trouble with deciding the correct solution I suggest we both make a text file of our possible cases and then we can see the subset of non-intersecting cases and decide.
EDIT: THIS IS WRONG, This logic generates cases which are not possible.
That’s what I am saying. my sequence will give 107 which I think is the highest achievable.
@Organic-Shilling : Oh no! Blunder! I selected 3,5,8,9,10,13 but made a calculation mistake! ( Selection 8 : Added 18 instead of 6 (wrong step)) Aagh!.. Anyways I wish I could upvote (low reputation)(started using forums lately but no repo yet) THANKS
EDIT: Can you explain your answer more clearly
My answers are
1a-3330000000
b-5322222
c-9666666666
2a-Dont know
b-Dont know
c-Dont know
3a-123
b-72
c-107
4a-10
b-7
c-11
Does anybody know answer of Q2 and how to solve it
I posted how I solved Question 2 Part A, turn to the previous page. Your Q1 part a appears to be wrong, Mine also has B = 33 but my number is greater than yours. Q4 part b is 9 and part c is 12.