why i am getting wa even though my prog is running for the given test case

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#include<stdio.h>

``````long int power(int n)
{
long int pro=1;

while(n)
{
pro = pro*5;
n--;
}
return pro;
}

int main()
{
int num=0;
long int arr[100000],t,temp,n,i,count=0;

scanf("%ld",&t);
temp = t;

while(t)
{
count=0;
num=1;
scanf("\n%ld",&n);

do
{
i = power(num);
if(i<n)
count= count+(n/i);
num++;
}while(i<n);
arr[temp-t]=count;
t--;
}

while(t<temp)
{
printf("%ld\n",arr[t++]);
}

return 0;
}``````

mention the question!

There is a single positive integer T on the first line of input (equal to about 100000). It stands for the number of numbers to follow. Then there are T lines, each containing exactly one positive integer number N, 1 <= N <= 1000000000.

Output

For every number N, output a single line containing the single non-negative integer Z(N).
where Z(N) gives the number of trailing zeroes in N!

Example

Sample Input:
6
3
60
100
1024
23456
8735373

Sample Output:
0
14
24
253
5861
2183837

well, thank you for asking but i got my answer. I was not checking for i=n condition in the while loop and if case.

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