#include<stdio.h>
#include<math.h>
int main()
{
int n;
scanf("%d",&n);
int b,a,c,diff[n],max_diff,diff1[n],diff2[n];
for(b=1;b<=n;b++)
{
scanf("%d %d",&a,&c);
diff[b]=a-c;
if (a>c)
{
diff1[b]=a-c;
}
else
{
diff2[b]=c-a;
}
}
max_diff=abs(diff[1]);
for (b=2;b<=n;b++)
{
if (max_diff>abs(diff[b]))
{
max_diff=max_diff +0;
}
else
{
max_diff=abs(diff[b]);
}
}
for (b=1;b<=n;b++)
{
if (diff1[b]==max_diff)
{
printf("1 %d\n",max_diff);
}
else if (diff2[b]==max_diff)
{
printf("2 %d\n",max_diff);
}
}
return 0;
}
it would help if provide a link to the question …
First thing you cannot say that if your code is giving correct answer for sample test case so you’ll get AC.
Secondly, your code gives WA for this test case…
15
140 82
89 134
90 110
112 106
88 90
129 112
2 69
0 67
220 34
13 579
246 456
121 20
4 950
146 674
941 897
Your code’s output: 2 946
Actual Output: 2 2083
Read this explanation again,:
Consider the following score sheet for a game with 5 rounds:
Round Player 1 Player 2
1 140 82
2 89 134
3 90 110
4 112 106
5 88 90
The total scores of both players, the leader and the lead after
each round for this game is given below:
Round Player 1 Player 2 Leader Lead
1 140 82 Player 1 58
2 229 216 Player 1 13
3 319 326 Player 2 7
4 431 432 Player 2 1
5 519 522 Player 2 3
The winner of this game is Player 1 as he had the maximum lead (58
at the end of round 1) during the game.
Error is:
You are not adding the previous score to the current score , i think you misunderstood problem.
You should add the previous score to the current score to calculate the lead .
See above mentioned second table you’ll understand the mistake… 
Or you may see my code here: http://www.codechef.com/viewsolution/5207511
I think the question is about The Lead Game.
Link => http://www.codechef.com/problems/TLG