In this problem, you have to implement a variation of Insertion Sort as described below.

Suppose X is an array of N positive integers to be sorted. In this scheme, another array Y is used to store the

sorted integers. This array is to be viewed as a circular array, ie. index (N-1)+1 = index 0 and index 0-1 =

index N-1. The sorted integers get stored in a circular manner in Y, ie, it is possible that the index of the

smallest integer may be greater than the index of the largest integer.

Eg. 6 8 _ _ _ 1 2 4 5 is a view of the array Y sometime into the algorithm. ’_’ indicates unused locations of

the array. Smallest integer 1 is at index 5, largest integer 8 is at index 1. So the sorted array in Y is to be

generated by printing the contents from index 5 to 1, assuming the array wraps around at the end, ie. after

index 8, the next index is 0.

Assume that h holds the index of the smallest integer in Y and t holds the index of the largest integer in Y.

Initially,

1. h = t = 0

2. Y[0] = X[0] ie. the first integer in X[] is copied as the first integer in Y[].

3. All other elements in Y[] are initialised to a dummy value -1.

The rest of the integers in X[] are now inserted one by one into Y[] such that Y[] always contains a sorted

list of integers, with the smallest integer at index h and the largest at index t. This is done in the following

manner:

Let I be the next integer from X[] to be inserted into Y[]. Scan the array Y downwards from index h (with

wrap-around at the end) till index t and find out the place in Y[] where I has to fit in.

If I fits in at either end

of the list, then insert it at the appropriate place in Y[]. Modify either t or h as appropriate to indicate the new

array structure; ie. either t is incremented or h is decremented (with wrap-around).

If I fits in somewhere in the middle of the list, then I should be inserted by shifting all the S smaller integers

one place to the left or by shifting all the L larger integers one place to the right, depending on the number of

integers to be shifted.

That is, if S < L, the smaller integers should be shifted one place to the left and if S >=

L, the larger integers should be shifted one place to the right. Again either h or t should be modified

appropriately.

Example

Integers to be sorted X[]: 25 57 37 48 12 92 86 33

Contents of Y[] after inserting each integer from X[]:

25 –1 –1 –1 –1 –1 –1 –1 Initially (t=0, h=0)

25 57 –1 –1 –1 –1 –1 –1 57 fits in at end (t=1)

25 37 57 –1 –1 –1 –1 –1 37 fits in middle, S=1, L=1, so shift 57 right. (t=2)

25 37 48 57 –1 –1 –1 –1 48 fist in middle, S=2, L=1, So shift 57 right. (t=3)

25 37 48 57 –1 –1 –1 12 12 fits in at beginning, circular property, (h=8, t=3)

25 37 48 57 92 –1 –1 12 92 fits in at end (t=4).

25 37 48 57 86 92 –1 12 86 fits in middle, S=5, L=1, so shift 92 right, (t=5).

33 37 48 57 86 92 12 25 33 fits in middle, S=2, L=5, so shift 12, 25 left (h=7, t=5).

Input Specification

The input will consist of a single line containing an integer N followed by the N integers to be sorted.

All

integers are positive and are separated by a single space. There will be no duplicates among the N integers.

Output Specification

The output should consist of N lines, each line containing N integers.

The N integers are the contents of Y[]

(ie. Y[0] to Y[N-1]) after the insertion of each integer from X[]. All integers on a line should be separated by

a single space. N will be less than 50.

Sample Input/Output

Input

8 25 57 37 48 12 92 86 33

Output

25 -1 -1 -1 -1 -1 -1 -1

25 57 -1 -1 -1 -1 -1 -1

25 37 57 -1 -1 -1 -1 -1

25 37 48 57 -1 -1 -1 -1

25 37 48 57 -1 -1 -1 12

25 37 48 57 92 -1 -1 12

25 37 48 57 86 92 -1 12

33 37 48 57 86 92 12 25