Using log for Huge Calculations

Is using log for calculation of huge number (floating point) saves precision ?? Consider these two solutions :



The concept for both solutions is almost same,in the second solution i am first calculating the last term and then to calculate and then calculating the previous term from current term because suppose we know the value of nck then to know the value of nCk-1 we need to multiply nCk by k and divide by (n-k+1) this gives us nCk-1.

I think since the question requires precision upto only 1 decimal place, so precision errors caused by log is nullified because anyways you’re rounding off the final answer to 1 decmal digit.