spellbob-whats wrong with my code

general
,
1

Whats wrong with the second one that i have written?-I have used gets() instead of scanf(),which i have used in the first code,for reading the strings and i was shown that it is a wrong answer.

#include<stdio.h>
void main()
{
int count;
char a[4];
char b[4];
scanf("%d",&count);
while(count–)
{
scanf("%s",a);
scanf("%s",b);
if((a[0]==‘b’||b[0]==‘b’)&&(a[1]==‘o’||b[1]==‘o’)&&(a[2]==‘b’||b[2]==‘b’))
printf(“yes\n”);
else if((a[0]==‘o’||b[0]==‘o’)&&(a[1]==‘b’||b[1]==‘b’)&&(a[2]==‘b’||b[2]==‘b’))
printf(“yes\n”);
else if((a[0]==‘b’||b[0]==‘b’)&&(a[1]==‘b’||b[1]==‘b’)&&(a[2]==‘o’||b[2]==‘o’))
printf(“yes\n”);
else
printf(“no\n”);
}
}

#include<stdio.h>
#include<string.h>
void main()
{
int count;
char a[4];
char b[4];
scanf("%d",&count);
while(count–)
{
gets(a);
gets(b);
if((a[0]==‘b’||b[0]==‘b’)&&(a[1]==‘o’||b[1]==‘o’)&&(a[2]==‘b’||b[2]==‘b’))
printf(“yes\n”);
else if((a[0]==‘o’||b[0]==‘o’)&&(a[1]==‘b’||b[1]==‘b’)&&(a[2]==‘b’||b[2]==‘b’))
printf(“yes\n”);
else if((a[0]==‘b’||b[0]==‘b’)&&(a[1]==‘b’||b[1]==‘b’)&&(a[2]==‘o’||b[2]==‘o’))
printf(“yes\n”);
else
printf(“no\n”);
}
}

2

first of all its very uncomfortable to understand your code here please update your code in a proper way using editor’s features.
and for a simple and descriptive solution have a look at my code after that if you have any doubt then you can ask here again with proper code updating.
in this link i am giving my code you can have a look.
link text

3

use “int main” instead of void main and try the following code:

#include<stdio.h>
int main (){
int count;
char a[4];
char b[4];
scanf ("%d", &count);
while (count–)
{
scanf ("%s", a);
scanf ("%s", b);
if ((a[0] == ‘b’ || b[0] == ‘b’) && (a[1] == ‘o’ || b[1] == ‘o’)
&& (a[2] == ‘b’ || b[2] == ‘b’))
printf (“yes\n”);
else if ((a[0] == ‘o’ || b[0] == ‘o’) && (a[1] == ‘b’ || b[1] == ‘b’)
&& (a[2] == ‘b’ || b[2] == ‘b’))
printf (“yes\n”);
else if ((a[0] == ‘b’ || b[0] == ‘b’) && (a[1] == ‘b’ || b[1] == ‘b’)
&& (a[2] == ‘o’ || b[2] == ‘o’))
printf (“yes\n”);
else
printf (“no\n”);
}

}