RAINBOWA python code wrong output

general
, ,
1

here is my python code:

code

q=“1234567”

k=[]

#function to omit test cases like 2 1 3 4 5 6 7 6 5 4 3 1 2
def is_increasing(n):

for i in range(int(len(n)/2)):

    
    if n[i]>n[i+1]:

        
        return False

    
return True

#function to check given array a rainbow array
def is_rainbow(n):

for i in range(len(n)):

    
    if n[i]==n[len(n)-i-1] and str(n[i]) in q and is_increasing(n):

        
        continue


    else:


        return False


return True

x=int(input())

for i in range(x):

s1=int(input())


s=list(map(int,input().split()))


if (is_rainbow(s)):


    k.append(1)


else:


    k.append(0)

for l in k:

if l==1:


    print("yes")


else:


    print("no")

can you please tell me whats wrong in my code.

2

Where are you calling the “is increasing” function? Also, what if your array is like

1 2 3 4 5 6 7 8 7 6 5 4 3 2 1

Above is not a rainbow array as it has an element more than 7, i.e. 8.

3

Yep, @vijju123 is right.

4

Here is my solution in python !

what i essentially did was checked for palindrome and increment the checking factor by one starting with zero and also note the middle element has to be 7 and rest all cases are false