if i am given a number how i find other two members of pithagorean triplet efficiently please post a tutorial including this.thanks

if given numbers as 1 or 2 then there is no solution after that u can use the property of Pythagorian triplets :

if n is odd

b=(n^2-1)/2

c=(n^2n+1)/2

if n is even

b=(n^2)/4-1

c=(n^2)/4+1

if u can print any triplet which includes n.this should help.

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