nzec error in java

general
, ,
1

question link =

i have also tried to apply quick sort in that question instead of Arrays.sort(a);
but still nzec error is there…(just giving it a try -_-)…

the code is working fine on ideone and eclipse.

my code :-

import java.io.;
import java.util.;
import java.math.*;
public class Main
{

public static void main(String[] args) 
{
	Scanner kb = new Scanner(System.in);
	int t = kb.nextInt();
	while(t-->0)
	{
		int n,m;
		n = kb.nextInt();
		m = kb.nextInt();
		int[] a = new int[n];
		for(int i=0;i<n;i++)
			a[i] = kb.nextInt();
		Arrays.sort(a);
		long count = 0;
		int ii = n-1;
		for(int i=n-1;i>=0;i--)
		{
			count+=a[i];
			ii = i;
			if(count>=m)
				break;
		}
		System.out.println(n-ii);
	}
}

}

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2

Solutions are not public currently (weird its an old problem, maybe this is currently featuring in some live contest ?!!).

3

@mediocoder i have posted the solution here…please have a look…

4

hey himanshu,
Even i code on java and used to have same problems.
Actually NZEC error on java occurs mostly due to some exceptions in I/O process.
You may use ‘try’ and ‘catch’ to remove those exceptions!
After that it will run perfectly.
try it using Try and Catch!
:slight_smile:

2 Likes
5

hey himanshu,
Even i code on java and used to have same problems.
Actually NZEC error on java occurs mostly due to some exceptions in I/O process.
You may use ‘try’ and ‘catch’ to remove those exceptions!
After that it will run perfectly.
try it using Try and Catch!
:slight_smile:

2 Likes
6

There are two main problems in your code for the said problem.

  1. Constraint is 1 ≤ M, P_{i} ≤ 10^{18}. So you need to use long datatype instead of int for m and also the array. This is the reason for NZEC.
  2. You are missing the output format for -1, read the output statements again. It says If it’s impossible to take at least M meatballs, print -1..You are not printing -1.

The corrected code is given below.

import java.io.*;
import java.util.*;
import java.math.*;
 
public class Main {
    public static void main(String[] args) 
    {
        Scanner kb = new Scanner(System.in);
        boolean flag;   // for the case where If it's impossible to take at least M meatballs, print -1.
        int t = kb.nextInt();
        while(t-->0)
        {
            int n;
            long m; // constraint for M is 10^18
            flag=false;
            n = kb.nextInt();
            m = kb.nextLong();
            long[] a = new long[n];   //constraint for Pi is 10^18
            for(int i=0;i<n;i++)
            a[i] = kb.nextLong();
        Arrays.sort(a);
        long count = 0;
        int ii = n-1;
        for(int i=n-1;i>=0;i--)
        {
            count+=a[i];
            ii = i;
                if(count>=m){
                    flag=true;
                    break;
                }
            }
            if(flag)
                System.out.println(n-ii);
            else
                System.out.println("-1");
        }
    }
}

Check the ACcepted code with the said modifications here.

1 Like
7

ok…i got it…
i have one more doubt…as i am new to java…
code_hard123 has said that i should use try and catch block…for this…
can you please tell me that why and when we are required to use this…?

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8

By using try-catch block you can overcome/ignore the NZEC but for this specific situation, try-catch block will not give you the correct answer. Instead of NZEC, the judge will give you some other NZEC or WA.

Here ( in codechef ), you rarely need ( almost never ) try-catch to solve the problems. Try-catch is used to handle exceptions.

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9

This exception handling in java is an astonishing, very very powerful feature and very very very much used in real world projects/programs. It is seldom used in competitive programming but you can use this if you want to.

If you have no idea ( as you said you are a beginner ) about try-catch then search in the internet or go through a book but it is usually not needed here.

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