Making Prims to run parallel

Hi All,

I found easy to understand code for sequential Prims Algorithm. 

Using openmp, I want to run it parallely.

I am only upto to send edges cost associated with each node to the processors

but unable to get results back that is MST edges, their costs and minimum cost.

This is my code: http://fpaste.org/169899/

//prims.c
// only able to send to 1 processor
#include <stdio.h>
#include <stdlib.h>
#include <omp.h>
#define DIM 1000

void initialization(void);
void delete_elements(int);

struct prim_data {
int edges_weight[DIM][DIM];
int dimension;
int U[DIM];
int total_min_distance;
int count_nodes_in_mst;
};

struct prim_data prim;

int main()
{
int ch,j,t,p_c,p_j,k,serial=1;
//int **prim.edges_weight[][]
int i;

//variable that holds the current maximum distance 
int min_distance; 

//variable that holds the next node in MST
int new_next_element;

prim.total_min_distance = 0; 
prim.count_nodes_in_mst = 0; 

//declaring the structs the are used by gettimeofday 
//struct timeval tb1; 
//struct timeval tb2; 
//setting the minimum distance 
min_distance = 1000; 

//opterr = 0; 
//parsing the arguments given 

printf("Enter the number of nodes:\n"); 
scanf( "%d", &prim.dimension); 
printf("Enter the cost of edges: \n"); 

for (i = 0; i < prim.dimension; ++i) { 
    for (j = 0; j < prim.dimension; j++) { 
        scanf("%d",&(prim.edges_weight[i][j])); 
         printf("Cost: %d ",prim.edges_weight[i][j]); 
          printf("From %d To %d\n",i,j); 
    } 
    //printf("\n"); 
} 


printf("\nPrinting the weight array...\n\n"); 

#pragma omp parallel default(none),private(i,j),shared(prim) 
{ 
int tid = omp_get_thread_num(); 
printf("thread %d starting\n",tid); 
#pragma omp for 
for(i=0; i<prim.dimension; i++){ 
    for(j=0; j<prim.dimension; j++) { 
        printf("%d\t\n",prim.edges_weight[i][j]); 
    } 
   } 
   //printf("\n"); 
} 

//initializing the data 
    initialization(); 

//calculating for all the nodes 
for(k = 0; k < prim.dimension -1; k++) 
{ 
    min_distance = 1000; 
    //for every node in minimum spanning tree 
    for(i = 0; i < prim.count_nodes_in_mst; i++) 
    { 
        //declaring OpenMP's derective with the appropriate scheduling... 
        #pragma omp parallel for 
            for(j = 0; j < prim.dimension; j++) 
            { 
            //find the minimum weight 
                if(prim.edges_weight[prim.U[i]][j] > min_distance || prim.edges_weight[prim.U[i]][j]==0) 
                { 
                    continue; 
                } 
                else 
                { 
                #pragma omp critical 
                   { 
                    min_distance = prim.edges_weight[prim.U[i]][j]; 
                    new_next_element = j; 
                    } 
                } 
            } 
     } 
    //Adding the local min_distance to the total_min_distance 
    prim.total_min_distance += min_distance; 
    //Adding the next node in the U set 
    prim.U[i] = new_next_element; 
    //Substructing the elements of the column in which  the new node is assosiated with 
    delete_elements( new_next_element ); 
    //Increasing the nodes that they are in the MST 
    prim.count_nodes_in_mst++; 
} 

printf("\n"); 
//Print all the nodes in MST in the way that they stored in the U set 
for(i = 0 ; i < prim.dimension; i++) { 
    printf("%d ",prim.U[i] + 1); 
    if( i < prim.dimension - 1 ) printf("-> "); 
  } 

  printf("\n\n"); 
  printf("Total minimun distance: %d\n\n", prim.total_min_distance); 
  printf("\nProgram terminates now..\n"); 
  return 0; 

}

void initialization(void) {

int i,j; 

prim.total_min_distance = 0; 
prim.count_nodes_in_mst = 0; 

//initializing the U set 
for(i = 0; i < prim.dimension; i++) prim.U[i] = -1; 

//storing the first node into the U set 
prim.U[0] = 0; 
//deleting the first node 
delete_elements( prim.U[0] ); 
//incrementing by one the number of node that are inside the U set 
prim.count_nodes_in_mst++; 

}

void delete_elements(int next_element) {

int k;
for(k = 0; k < prim.dimension; k++) {
prim.edges_weight[k][next_element] = 0;
}
}