MAGICAL TRANSFORMATION

Its a question on minimum distance or the minimum steps required to convert a given String to another String.The Only addition step here is that we can swap 2 variables.
Here is the Link Of the question:http://www.codechef.com/INLO2015/problems/MOUSCH01
Now this can be solved by DP.In the case of swap I have used an additional step which is in my solution

#include<stdio.h>

#include<string.h>

#define LARGE 100000

int T[101][101];

char a[101];

char b[101];


int MIN(int a, int b) {

 return a < b ? a : b;

}

int min(int a,int b,int c){

 return MIN(MIN(a, b), c);

}

void dispaly(int m,int n){

 int i,j;

 for(i=0;i<=m;i++){

    for(j=0;j<=n;j++)

       printf("%d ",T[i][j]);

  printf("\n");
 }

}
int minChange(char *a,char *b,int m,int n){

int i=0,j=0,u,v,w,x,a1,b1=LARGE;

  char t;

for(j=0;j<=n;j++){
   T[0][j]=j;
 
}

for(i=0;i<=m;i++){

  T[i][0]=i;

}
//dispaly(m,n);

for(i=1;i<=m;i++){

for(j=1;j<=n;j++){

   u=T[i-1][j]+1;

   v=T[i][j-1]+1;

   w=T[i-1][j-1]+(a[i-1]!=b[j-1]);
  
   a1=min(u,v,w);

  //The case Of swapping is checked  



  if(j>=2){
    if(a[i-1]==b[j-2]&& a[i-2]==b[j-1])
      b1=T[i-2][j-2]+1;
  }
  a1=MIN(a1,b1);


   T[i][j]=a1;
     
}
b1=LARGE;

}

return T[m][n];

}
int main(){

int t=0,l1,l2;

scanf("%d",&t);

while(t-- > 0){

  scanf("%s%s",a,b);

  l1=strlen(a);

  l2=strlen(b);

  printf("%d\n",minChange(a,b,l1,l2));
 
}
//getch();

return 0;

}

The question is similar to the:http://www.geeksforgeeks.org/dynamic-programming-set-5-edit-distance/
only the the addition step in the question is of swapping

I am getting wrong ans plz help

:stuck_out_tongue:

The substructure is given in the article.

http://www.codechef.com/viewsolution/6810175 My solution for reference.

Can you suggest about the Transposition Step??How They are calculatiing

Terima kasih dan salam kenal.
codechef Link

code Link