low level const and top level const function overloading

general
,
1

I have three functions:

#include <iostream>

  1. Which takes parameter as normal: int*

    void func(int * para)
    {
    std::cout << “Printing function without const” << *para << std::endl;
    }

  2. Which takes parameter as low level const: const int* para

    void func(const int *para)
    {
    std::cout << “Printing function with low level const” << *para << std::endl;
    }

3)Last which takes parameter as top level const: int *const para

void func(int *const para)
{
std::cout << "top level one" << *para << std::endl;
}

Ques1) One & two are perfect overloaded functions but one and three aren’t why?

int main()
{
int j= 4435;
const int i = 34; 

func(&j);    //For first function
func(&i);    //For second function

// But then i have to remove 3rd function from the code because in that case overloading fails? Why exactly that happens?

return 0; 
}

Ques 2) As I know

int j =34 ;

const int *ptr = &j;

const can also take non-const. So, why even the second function is considered as overloaded function?

2

const int *para

is a pointer to an integer constant and

int *const para

is a constant pointer to an integer. How can they be same? You are understand the other way round I suppose.

3

I am not saying they are same. I have mentioned my Questions explicitly please read them again.