Hi I need to come up with a solution for the following problem. Tell me how to code in C?
Input:
1 2 3 4
Output:
1 2 3 4
4 1 2 1
3 4 3 2
2 1 4 3
Hi I need to come up with a solution for the following problem. Tell me how to code in C?
Input:
1 2 3 4
Output:
1 2 3 4
4 1 2 1
3 4 3 2
2 1 4 3
Having a problem statement would make things easier. It looks like a permutation of the input repeated 4 times but what exactly are you trying to achieve? You have to help us help you.
what if my answer is
#include<stdio>
int main(){
printf("1 2 3 4\n");
printf(" 4 1 2 1\n");
printf("3 4 3 2\n");
printf("2 1 4 3\n");
return 0;
}
Bad right , the same is your question
i think he wants to print it in spiral form!!!
if this is ne kind of homework…then pls do it yourself…try it…if u get stuck somewhere then ask…and provide your code…it is easy…just give it a shot!!!
nice gesture Will implement it now Thanx for the explanation
This answer just made my day
Have a look at below codes
In main use w = 4 and h = 4.
Moreover in cout (while printing), numbers larger than 4 to smaller numbers.
hahaha
lol good one
Google search spiral matrix implementation
Thanks a lot… I find it difficult to understand your logic… I must spend some time with the code to crack it…
You can initialize the matrix with all -1. (-1 means not visited)
Start with (x = 0, y = 0), written = 0
while x < width && arr[x][y] == -1, arr[x++][y] = next number, ++written.
–x, ++y
while y < height && arr[x][y] == -1, arr[x][y++] = next number, ++written.
–x, --y
while x >= 0 && arr[x][y] == -1, arr[x–][y] = next number, ++written.
++x, --y
while y >= 0 && arr[x][y] == -1, arr[x][y–] = next number, ++written
++x, ++y
if written != width * height, go to step 2
Try to implement this, if you find anything difficult do post it.