Last Digit Sum(http://www.codechef.com/COOK14/problems/LASTDIG)

general
1

I have spen hours on this code figuring out what went wrong.I am not getting why this is not showing the output.

 # include <stdio.h>
 #include <conio.h>
 int main()
 {
int a,i,j,dig,sum1=0,sum2=0,k,b,c,o;

    scanf("%d",&a);      
  for(k=0;k<a;k++)             // For test cases
  {
    scanf("%d",&b);
    scanf("%d",&c);
    for(j=b;j<=c;j++)         //scanning the two numbers.
    {  
    while(j!=0)
    {sum1=0;
    dig=j%10;
    if(dig%2==0){sum1=(sum1+(2*dig));}
    else{sum1=(sum1+dig);}                    //finding the sum of digits.If digit is even 
    j=j/10;                                       multiply it by 2 and add if it is odd simply

` } just add

    o=sum1%10;      
    sum2=sum2+o;                             //finding last digit of the sum.

    }
    printf("%d",sum2);                      //printing sum2 which is sum of all the last digits 
    sum1=0;                                  of sum1
    }          
    getch();
    return 0;

}

2

what is the question code?

3
4
5

in the for loop,you use j as counter…
and in its inner while loop you change the value of j…
by j=j/10;
moreover
you have to initialise sum1 and sum2 inside the test case loop…
so that they should be zero for every new case.

6

you have to remove conio and getch as well

7

ok thnx…:slight_smile:

8

Pls can you correct it for me,.

9

include <stdio.h>

// #include <conio.h>
int main()
{
long long int a,i,j,dig,sum1=0,sum2=0,k,b,c,o,n;

scanf("%lld",&a);

for(k=0;k<a;k++) // For test cases
{
scanf("%lld",&b);
scanf("%lld",&c);
sum2=0;
for(j=b;j<=c;j++) //scanning the two numbers.
{
n=j;
sum1=0;
while(n!=0)
{
// sum1=0;
dig=n%10;

if(dig%2==0)
sum1=(sum1+(2*dig));
else
sum1=(sum1+dig);                    //finding the sum of digits.If digit is even

n=n/10;                                 //      multiply it by 2 and add if it is odd simply
 }
o=sum1%10;
sum2=sum2+o;                             //finding last digit of the sum.

}
printf("%lld\n",sum2);                      //printing sum2 which is sum of all the last digits
sum1=0;                 //                 of sum1
}

// getch();
return 0;

}
vote my ans :slight_smile: