largest good subarray - score 15% - what is the basis of scoring?

general
, ,
1

My code solves many test cases. But score is only 15%. May i know the method of scoring and code suggestion

Here is my code:

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#include

int main()
{
int T, cols, k, i;
//std::cout << "Number of test case " << std::endl;
std::cin >> T;
if(T>10) {
return 0;
}
int good[T];

for(k=0;k<T;k++) {

    //std::cout << "Enter size of array " << std::endl;
    std::cin >> cols;
    if(cols > 100000) {
        return 0;
    }
    int i,j,m=0;
    int* matrix = new int[cols];

    //std::cout << "Enter Elements : " << std::endl;
    for(j=0;j<cols;j++) {
        std::cin >> matrix[j];
        if(matrix[j] > 1000000000) {
            return 0;
        }
    }
    
    /*for(j=0; j<cols;j++) {
        std::cout << "Element : " << j  << " : " << matrix[j] << "\n";
    }*/
    
    for(i=0; i<cols; i++) {
        for(j=i+1; j<cols;j++) {
            if(matrix[i] > matrix[j]) {
                if(j-i+1 > m) m=j-i+1;
            }
        }
    }
    
    good[k] = m;
    //std::cout << "Highest is : " << m << "\n";
}

for(i=0; i<T; i++) {
    std::cout << good[i] << "\n";
}
return 0;

}

2

Generally you only “score” a particular section if all of the test cases in that section are achieved. So for example you could solve 9 test cases out of 12 in a question with 3 scoring sections and still score zero, if one test case in each section failed. If you look at your submission on a subdivided task assessment there should be a table (below the code) that shows you why the failed test cases failed; I wouldn’t be surprised if the issue was “TLE”, time limit error, which often means you need a different (faster) algorithm.

Also please edit your question: highlight the code section and press the “code” format button; this will indent it all another 4 spaces and show it properly on screen.

Also, when you are editing, can you add the direct link to the question you are working on? (I don’t see any recent exercise submissions associated with your forum profile here.)