#include

using namespace std;

int main(){

int n;

cin>>n;

int no[n][2];

int div[n];

for(int i=0; i<n; i++){

for(int j=0; j<2; j++){

cin>>no[i][j];

}

}

for(int i=0; i<n; i++){

for(int j=0; j<2; j++){

div[i]=(no[i][1])/(no[i][2]);

}

}

for(int i=0; i<n; i++){

cout<<div[i]<<endl;

}

return 0;

}

Provide the problem name and/or code or the problem itself.

Code-> FLOW002

It is told that you need to find the remainder when A is divided by B, i.e. you need to find A%B. As I can see that you have written:-

**div[i]=(no[i][1])/(no[i][2]);**

You need to write it as div[i] = (no[i][1])(no[i][2]), since operator when used as A%B, calculates the remainder when A is divided by B(modulus).

Eg.:- If A = 8 and B = 5, then A%B = 3, since when 8 is divided by 5, you get 3 as remainder.

If A = 5 and B = 9, then A%B = 5, since when 5 is divided by 9, you get 5 as remainder(9*0 + 5).

As I can see that you have just started competitive programming. You can refer to this code for a better coding style:- see this code.

Hope this solves your problem. If you have any more doubt please ask.