#include

#include<math.h>

using namespace std;

int main()

{

int x,n, y;

cin >> n;

if (n>1 && n<1000)

while (n–){

cin >> x ;

if (x>1 && x<10000)

x=x/2;

y=(0.5*x*x)-(0.5*x);

cout << y << endl;

}

}

#include

#include<math.h>

using namespace std;

int main()

{

int x,n, y;

cin >> n;

if (n>1 && n<1000)

while (n–){

cin >> x ;

if (x>1 && x<10000)

x=x/2;

y=(0.5*x*x)-(0.5*x);

cout << y << endl;

}

}

Mate,

The answer is really simple…

Observe the answers and try to find a sequence similar to that…

I won’t reveal the sequence here, so i don’t spoil the fun…

If still unable to solve, Have a look at this code…

Accept answer if you find this helpful…

Feel free to ask anything…