HS08TEST: Getting WA

I have got a solution for this problem, and I have got the right output, but the checker tell me it is wrong answer:

import java.util.Scanner;
class Atm {
    public static void main(String[] args) {
    Scanner bill=new Scanner(System.in);
    String darabol[] = null;
    String beolvas=bill.nextLine();
    darabol=beolvas.split(" ");
    double darabolszt[] = new double[darabol.length];
    for(int i=0;i0 && darabolszt[0]<2000)
    if(darabolszt[1]>0 && darabolszt[1]<2000)
    if(darabolszt[0]%5!=0.0){
    System.out.format("%.2f%n",darabolszt[1]);    
    }
    else if(darabolszt[0]>darabolszt[1]){
    System.out.format("%.2f%n",darabolszt[1]);
    }
    else{
    System.out.format("%.2f%n",(darabolszt[1]-darabolszt[0])-0.50);
    }
    }
}

```

I can explain you the procedure for that problem in C++.

But if your question is to find out bug in your java program. Hope for someone else to help :slight_smile:

Comparing both the programs ( Algorithms ) will let you know the mistake.

Look out the comments in program for explanation :slight_smile:

Happy Coding :slight_smile:

#include <iostream>
using namespace std;
 
int main()
{
int p;
float q;
cin>>p>>q;       //Scan In Inputs
if(p%5!=0)       //Check if p is a multiple of 5
cout<<q<<endl;   //If not, Transition is not valid, And so just print q value
else if(p+0.5>q) //Check if there are enough funds. +0.5 for cutting charges
cout<<q<<endl;   //Again if not print q;
else             //So finally all conditions satisfied
{
q=q-p-0.5;       //Deduce the amount
cout<<q<<endl;   //Print q
}
return 0;
}
1 Like
if(darabolszt[0]>darabolszt[1])

this test is unfortunately wrong.

you should consider the corner case when there is not enough money to include the fee of the withdrawal. :slight_smile:

Generally you should use english variable, function name it would more easy to read your code who are not hungarian :slight_smile:

2 Likes

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