Is there any O(n) solution to this problem
Using 2 pointers, pL and pR, tracing cost sum between pL…pR.
Initially pL=pR=1; if cost above limit, advance pL; otherwise advance pR.
Recording the maximum cost below M during the process. When pR > N, you get the global maximum.
i applied the same logic .
But is there any better logic?
It is already O(n). what type of logic do you expect?
can u please explain it using kadane’s algorithm?