The third example test case provided in problem SEATSR of October long challenge is not clear to me.
The test case is -
Input-
baaaaa
aaaaab
1 100 100
Output-
2
How can the answer be 2 for that. For me it is 4.
Please someone explain this to me.
Thanks.
U can delete the ‘b’ from the start and then add it to the end. 1+1=2, 1 for insertion, 1 for deletion.
Phheww…finally. Thanks a lot. 
best of luck!
ohh…just 1 more thing…what i know is this -
say if we have BAABAAB and AABAABB, we can remove first B and add to the end.
But in case of AABAAA and AAAAAB we cannot just pop the B and add it to the end.
For this we have to remove first 2 A’s and B and then add all three A’s.
Is it so?
Thanks again.
Nope u can! Its written clearly… Remove a character from any position of the string. ANY position. U can directly delete b and add one B to the end.