### PROBLEM LINK:

**Author:** Nikhil Ramakrishnan

**Tester:** Nikhil Ramakrishnan

**Editorialist:** R. Ramana

### DIFFICULTY:

SIMPLE

### PREREQUISITES:

Calculating percentages.

### PROBLEM:

You are given the number of sentences P and a list of numbers

depicting the number of words that are same/plagiarized in the respective sentence. You are also given the minimum number of

words K that must be same in a sentence for the sentence to be considered as plagiarized.

### QUICK EXPLANATION:

Check if the more than 40% of the integers are greater than N.

### EXPLANATION:

To solve this question, we first flag which sentences are plagiarized, to do this we check

the number of common words in each sentence and compare it with the minimum number of allowed common words, K.

If we represent the number of common words in a sentence as n[1], n[2], n[3], ..., n[P]

then we check if n[j] >= K for j in [1, P].

If n[j] comes out to be more than or equal to K then the sentence is considered to be plagiarized.

Let us represent the number of plagiarized sentences by PlagNumber and initialize it to 0.

Now whenever we encounter a plagiarized sentence we will increment PlagNumber by one.

Once we have the total number of plagiarized sentences (PlagNumber) for the case, we calculate the plagiarism percentage (say PlagPercentage)

by dividing the total number of plagiarized sentences PlagNumber with the total number of sentences P and then multiplying the result with 100.

Finally we check if the plagiarism percentage is more than 40%, if so we give the output as `FAIL`

otherwise the output will be `PASS`

.

An algorithm for this would look something like this:

```
PlagNumber = 0
for (i = 1 to P)
{
if (n[i] >= K)
{
PlagNumber = PlagNumber + 1
}
}
PlagPrecentage = (PlagNumber/P) * 100
if ( PlagPercentage > 40)
{
Output("FAIL")
}
else
{
Output("PASS")
}
```

### Time Complexity

O(N)