Ceil A-B ,What's wrong with my code ?

general
, ,
1

//It’s the code for Ceil A-B problem in practice set

#include<stdio.h>

int main()
{
    unsigned long a=0;
    unsigned long b=0;
        scanf("%lu %lu", &a, &b);
        printf("%lu\n",(a-b));
        printf("%lu\n", (a-b)^1);
    return 0;
}
2

You should not output the first line i.e. remove printf("%lu\n",(a-b)) .

1 Like
3

#include<stdio.h>

int main()
{
    unsigned long a=0;
    unsigned long b=0;
        scanf("%lu %lu", &a, &b);
        printf("%lu\n", (a-b)^1);
    return 0;
}

Again wrong…
What can i do ?
My way of implementation is correct ?

4

remove printf("%lu\n",(a-b)^1);
because we can not write ^

5

When a-b = 1 your answer will be zero , but it has leading zeroes . So it is giving WA .
Here is your corrected code .

# include < stdio.h>
int main()
{
    unsigned long a=0;
    unsigned long b=0;
    unsigned long ans=0;
    scanf("%lu %lu", &a, &b);
    ans=(a-b)^1;
    if (ans==0)
        ans=2;
    printf("%lu\n",ans); return 0;
}
1 Like
6

Thanks. I forgot that fact. Now ok. Once again thank you.