Hello friends can someone tell me how to approach this problem ? I am getting WA.
@vijju123 @taran_1407 @vivek_1998299 @meooow @john_smith_3 @aryanc403 @vbt_95
Here is my latest submission. If it’s too messy, here is the approach I used :
n =readInt()
arr = readInts()
count = 0
for i in range(len(arr)):
count+=1
f =0
minus = arr[i]
for j in range(len(arr)):
arr[j]-=minus
for j in range(len(arr)):
if arr[j]>0:
f =1
if f==0:
break
print(count)
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You’ll need to subtract the MINIMUM element of the segment from each element of the segment. By segment I mean, a contiguous range, surrounded by a 0 at both sides.
Eg. 1, 4, 7, 0, 4, 0, 7, 8 has three segments; 1 is minimum of the first segment, 4 of the second and 7 of the third segment.
Try the simple test:
2
2 1
Your code gives 1 as answer, but you need atleast 2 cuts.
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At least make sure arr[i] > 0 before subtracting it from the whole array.
n =readInt()
arr = readInts()
count = 0
for i in range(len(arr)):
count+=1
f =0
minus = arr[i]
if minus <0:
continue
for j in range(i,len(arr)):
arr[j]-=minus
for j in range(i,len(arr)):
if arr[j]>0:
f =1
if f==0:
break
print(count)
@sarthakmanna here is the approach where am I missing. Also for 100 points I feel it’s too slow.
I was trying to explain this approach: https://www.codechef.com/viewsolution/19150087
For 100pts, you can use a stack or priority queue like this: https://www.codechef.com/viewsolution/19011529
The 100pt solution is written in Java. I hope you’ll have no problem in understanding it. However, if you have any, feel free to ask.
1 Like
thanks man I got it now. Let me code it out using stack