Problem Link :
Contest
Practice
Author: Amrutansu Garanaik , Abhishek Patnaik
Tester: Keshow Sablaka, Amit Das
Editorialist: Amrutansu Garanaik , Amit Kumar Sahu
Difficulty :
easy
Pre-requisite
union-find algorithm
## Problem :
Given a set of nodes of a graph and edges connecting the nodes. Then some queries of the form a b are given. You have to print whether or not a and b are in same connected component of the graph.
Explanation
The problem is a simple application of union-find algorithm. Union-find algorithm creates sets of elements present in same connected component. For an edge connecting node a and b, use union(a,b). The find operation works in O(logn) time and gives the answer. If find(a) == find(b), then both nodes are in same component, otherwise they are in different components.
Union-find algorithm can be learnt here
Note : We can also perform a dfs or bfs on the graph to find the answer, but the constraints were high preventing this approach.