ATM: "wrong answer"

general
1

#include<stdio.h>
int main()
{
float x,y;

scanf("%f %f",&x,&y);
if(((int)x%5==0) && (x + .5 <= y)) 
printf(".2f",y-x-.5);
else
printf(".2f",y);
return 0;

}

2

Please check your output file. You will understand your mistake.
Your approach is right.

3

in printf function add \n and submit your answer

1 Like
4

#include<stdio.h>
int main()
{
int m;
float n,r;
scanf ("%d%f",&m,&n);
if( m%5 ==0 && m < n){
r = n-m-0.5;
printf("%0.2f",r);
}
else
printf("%0.2f",r);

return 0;

}

5

And, what might this be ??

2 Likes
6

You do not need to print new line as there is only one input…the error in your code is that you have forgotten to add % in the format specifier of printf function.

2 Likes
7

The errors with your code is

printf(".2f",y-x-.5);

is supposed to be

printf("%.2f",y-x-.5);

and

printf(".2f",y);

is supposed to be

printf("%.2f",y);

If you do not add the format specifier %,then printf() will just output what is inside your double quotes. Well, hope this solves your problem.

1 Like
8

please check your program properly … There are some syntax errors.

if u are unable to find them … i will help u then.