CAOS2 - Editorial

@betlista NO!! p[i] contains number of primes from 1 to i

for(i=2;i<250;++i) p[i]=1;

for(i=2;i<250;++i){

	if(p[i]==1){

		for(j=2*i;j<250;j+=i)

			p[j]=0;

	}

}

p[0]=p[1]=0;

for(i=2;i<250;++i) p[i]+=p[i-1];

Thanks.

I see, I missed += O:-)